[新しいコレクション] p(x)=ax a≠0 132501-P(x)=ax a#0
Because (a 1) 2 = a, a 1 is the unique solution of the quadratic equation x 2 a = 0 On the other hand, the polynomial x 2 ax 1 is irreducible over F 4, but it splits over F 16, where it has the two roots ab and ab a, where b is a root of x 2 x a in F 16 This is a special case of Artin–Schreier theoryAn1 0 ∞ ∫ Integration by Parts UdV a b ∫="#UV$% a b −VdU a b ∫ U and V are functions of xZero of the polynomial p (x)=ax,a≠0 2 See answers Wnvh5 Ltew4p0m P(x)=ax a#0